Q
1. Terlampir
2. 7! × 3! ÷ 2! =
3. 5³ + 2x
x => 5
1. Terlampir
2. 7! × 3! ÷ 2! =
3. 5³ + 2x
x => 5
Jawaban
1.
[tex] \sqrt[3]{343} \\ = 7 {}^{3} \\ = 7 \times 7 \times 7[/tex]
2. 7! × 3! ÷ 2!
= (7 × 6 × 5 × 4 × 3 × 2 × 1) × (3 × 2 × 1) ÷ (2 × 1)
= (42 × 5 × 4 × 3 × 2 × 1) × (6 × 1) ÷ 2
= (210 × 4 × 3 × 2 × 1) × 6 ÷ 2
= (840 × 3 × 2 × 1) × 6 ÷ 2
= (2.520 × 2 × 1) × 6 ÷ 2
= (5.040 × 1) × 6 ÷ 2
= 5.040 × 6 ÷ 2
= 30.240 ÷ 2
= 15.120
3. 5³ + 2x
x => 5
5³ + 2(5)
= (5 × 5 × 5) + 10
= (25 × 5) + 10
= 125 + 10
= 135
Jawaban:
1). 7
2). 15.120
3). 135
Penjelasan dengan langkah-langkah:
1). ³√343
= ³√7³
= 7
2). 7! × 3! ÷ 2!
= 7.6.5.4.3.2.1 × 3.2.1 × 2.1
= 5.040 × 3
= 15.120
3). 5³ + 2x
= 5³ + 2(5)
= 125 + 10
= 135
[answer.2.content]
